[1] 4 x 5 = 20 y = 3 i = 5 x = 2.5 y = 8 x = 3.0 [2] 5 x 4 = 20 a) 1) ans1 = 90 ans1 = 100 ans2 = 110 2) ans1 = 24 ans1 = 34 ans1 = 44 ans2 = 44 b) 1) ans3 = 90 ans3 = 100 ans4 = 110 2) ans3 = 24 ans3 = 34 ans3 = 44 ans3 = 54 ans4 = 54 [3] 10 n = 6 [4] 10x2 = 20 a) x-x-x-x*x b) switch(a){ case ' ': case '+': a = '-'; break; case '/': a = '*'; break; default: a = 'x'; } [5] 15 #include int sub(int n); main() { int num=10; printf("NUM = %d\n", sub(num)); } int sub(int n) { return n*n*n; } [6] 15 p = a; q = b; while(*p != '\0') *q++ = *p++; *q = *p; あるいは、 p = a; q = b; do{ *q++ = *p; while(*p++ != '\0')